**1. Roots (solutions) to a polynomial in a single variable**

Quite why I was not taught this for ‘A’ level maths is beyond me (or more likely I was and have simply forgotten) but, if we have a polynomial in a single variable:

Then the general form of its factorisation is:

and it has the roots:

Here’s an (very) outline proof…

Take a polynomial with a known root then will divide evenly (no remainders) by and so we can say where is of one degree less than . We can continue this until we are left with a function of degree 0 – i.e. the constant (possibly 1) and then we have the form .

(And I recommend Elliptic Tales: Curves, Counting, and Number Theory for those who want to know more – I am on my second iteration of trying to read this, but it is good fun.)

**2. I can construct a curve that has no tangent at any point**

At least, algebraically, it has no tangent.

For instance, the line defined by .

We define the tangents for such lines, as, at the point as being of the form:

Now, , but note that and are also equal to zero for all points, so we have which describes no line.

But – *geometrically* – this line is the same as that described algebraically by which has a tangent line of .

Are they different lines? They are, algebraically.

(This comes from the same source as point 1).

### Like this:

Like Loading...

*Related*

## Published by Adrian McMenamin

Talk to the hand
View all posts by Adrian McMenamin

Regarding roots, in general some are complex. Perhaps that delayed coverage of polynomial factorization?

I just think I must have forgotten this. I even a year of maths at university (though it was more “maths recipes” than theory) and so I cannot believe we weren’t taught this.