The maths of the spirograph… with the drawings

Well, I sat down and thought this was going to be easy, but it has taken me three hours to work the maths of a smaller inner wheel rolling around inside a large outer wheel: mainly because for the first two of those I neglected the basic insight that the inner wheel rolls in the opposite direction to its direction of travel (think of it this way – as a car wheel moves forward the point at the top of the wheel moves backwards – relative to the centre of the wheel).

And instead of using MetaPost I resorted to a spread sheet – though I might do a MetaPost drawing still.

Anyway – assume you have a big wheel of unit radius and a small wheel inside it of radius $\frac{1}{R}$ .

At any given time the centre of this small wheel will be at cartesian co-ordinates (assuming the big wheel is centred on (0,0):

( $cos(\theta)(1 -\frac{1}{R})$ , $sin(\theta)(1 -\frac{1}{R})$ ) (1)

where $\theta$ is the angle of rotation of the small wheel relative to the centre of the big wheel.

But if the small wheel has moved through angle $\theta$ relative to the centre of the big wheel, then it will have itself rotated through the angle $R\theta$ – in the opposite direction to its rotation around the centre of the big wheel.

This means a fixed point on the surface of the small wheel will now be, compared to the centre of the smaller circle, at cartesian co-ordinates:

( $\frac{cos(\theta - R\theta)}{R}$ , $\frac{sin(\theta - R\theta)}{R}$ ) (2)

And we add (1) and (2) together to get the co-ordinates relative to the origin (ie the centre of the bigger circle).

Looking at the above it should be relatively obvious that if $R$ is an integer then the pattern will represent $R$ cusps – and not much less obvious is the fact that if $\frac{1}{R}$ can be expressed as a rational number then the pattern will repeat. But if $\frac{1}{R}$ cannot be expressed as a rational then it turns out there are a countably infinite number i.e., $\aleph_0$ , number of cusps. In a way this is just a graphical way of representing an irrational number – it is a number that cannot be made to divide up unity (the circle) into equal proportions.

So here are the pretty pictures:

Let $R = 2$ and we have a degenerate case –

Then the 3 cusps of the ‘deltoid’:

The four cusped astroid:

And, here is the spreadsheet:
spirograph spreadsheet

Bra-Ket notation and it’s uses (awouo.wordpress.com)
How to build a teleportation machine: Intro to entanglement (quantumfrontiers.com)
Answer to Problem of the Week for 11 August – 17 August 2012 (mikepoliquin.com)
Create shapes like cones with Client Graphics (adndevblog.typepad.com)

Author: Adrian McMenamin

Talk to the hand View all posts by Adrian McMenamin

2 thoughts on “The maths of the spirograph… with the drawings”

Thanks kindly for working this out. I have the dread suspicion that if I’d worked it out on my own I wouldn’t get the interior wheel orientation correct for an embarrassingly long time.

Adrian McMenamin says:

September 6, 2012 at 9:43 am

I had drawings in the book – so knew what I was after, but my figures did not look like the book at all, so had to work out why that was.

Comments are closed.

Related articles

Rate this:

Share this:

Like this:

Related

Author: Adrian McMenamin

2 thoughts on “The maths of the spirograph… with the drawings”